Dim m2 As String

Private Sub Command1Click()

Dim flag(1 To 26) As Boolean

Dim num As Integer,t As Integer

Randomize

num = 1

Text3.Text = " "

For i = 1 To 26

    flag(i) = False

Next i

Do While num <= 26

    x = Int(Rnd * 26) + 97

          ①      

    If  flag(t) = False Then

    m2 = m2 + Chr(x)

    num = num + 1

      ②       

    End If

Loop

Text3.Text = m2

End Sub

Private Sub Command2Click()

Dim s As String， m As String， result As String

Dim k As String， c As Integer

s = Text1.Text

m = "abcdefghijklmnopqrstuvwxyz"

For i = 1 To Len(s)

    k = Mid(s, i, 1)

    If  k >= "A" And k <= "Z"  Then

    k = Chr(Asc(k) + 32)

    End If

    c = 1: continue = True

    Do While       ③       

    If k = Mid(m, c, 1) Then

    continue = False

    End If

    c = c + 1

    Loop

   ④     

Next i

Text2.Text = result

End Sub

程序①处的代码是{#blank#}1{#/blank#}

程序②处的代码是{#blank#}2{#/blank#}

程序③处的代码是{#blank#}3{#/blank#}

程序④处的代码是{#blank#}4{#/blank#}

首先，分别求出特加密ASCII字符的ASCII码，然后用7位二进制来表示，比如“4”的ASCII码为十进制52，转换为7位二进制为“0110100”

其次，从左至右依次记为第1、2、3....7位，分别把第3、4、5位取反，即0变1， 1变0，至此“0110100”变为“0101000”，将此二进制转换为ASCII码为40，对应的字符为“(”，即“4”经过加密后得到加密字符左括号“(”。

在文本框Text1中输入ASCII字符，单击命令按钮Command，则在文本框Text2中显示经过加密的字符。VB代码如下，程序界面如图所示。

上述加密与解密过程实际上是可以互逆的，请完成下列问题。