def data_sort(a):

    for i in range(len(a)):

        for j in :

            if   ①    :

                a[j], a[j+1] = a[j+1], a[j]

①划线处填入的语句为，可实现上述功能。

②若将加框处语句写错为 range(i,len(a)-1)，则下列 4 组数据中，若列表a 的值为（单选，填字母）不能测试出问题。

A. [['A1',100,30],['A2',120,30],['A3',110,30],['A4',140,30],['A5',130,30]]

B. [['A1',120,30],['A2',110,30],['A3',100,30],['A4',130,30],['A5',140,30]]

C. [['A1',110,30],['A2',140,30],['A3',130,30],['A4',100,30],['A5',120,30]]

D. [['A1',110,30],['A2',120,30],['A3',130,30],['A4',140,30],['A5',100,30]]

def huan(n):

    #将分钟转换为时间AA:BB 格式，返回值为字符串，代码略#读取文件中的信息，并存储在列表 order 中，代码略data_sort(order)

n=int(input("机器数量：")) for i in range(len(order)):

    order[i].append(-1)#order[i]追加一个元素-1 mach = [-1] * n

num, wait = 0, 0

for i in range(len(order)):

    k = -1

    time = -1

    for j in:

        t1 = mach[j]

        if k == -1:

            k = j

            time = order[t1][1]+order[t1][2]

        else:

            t2 = mach[k]

            if order[t1][1]+order[t1][2]<order[t2][1]+order[t2][2]:

                k = j

                time = order[t1][1]+order[t1][2]

    if k == -1 or num < n and:

        mach[num] = i

        num += 1

    else:

        order[i][3] = mach[k]

        mach[k] = i

        if time > order[i][1]:

            wait += time-order[i][1]

            order[i][1] = time if num < n:

    print("只需开启"+str(num)+"台机器") else:

    print(str(n)+"台机器全部开启，订单平均等待"+str(round(wait/len(order),2))+"min") for i in range(num):

    print('第'+str(i+1)+'台机器：')

    p = mach[i]

    ans = ''

    while p!=-1:

        ans = order[p][0]+':'+huan(order[p][1])+'~'+huan(order[p][1]+order[p][2])+'，' + ans

        p = 

    print(ans[:-1])