实现上述功能程序如下，在横线处填入合适的代码。

Dim n As Integer

Dim a(1 To 50) As Integer

Sub makedata(s As String)     ‘该过程实现将输入的体重分别存入数组a中

Dim in As Long, x As Long, c As String, i As Integer

m=Len (s) : n=0

For i=1 To m

 c=Mid(s, i, 1)

 If c >=“0” And c <=“9” Then

  {#blank#}1{#/blank#}

  x=x+Asc(c)-Asc(“0”)

 Else

  If x > 0 Then n=n+1: a(n)=x

  x=0

 End If

Next i

n=n+1: a(n)=x

End Sub

Private Sub Command1_Click()

Dim s As String, i As Integer, j As Integer, t As Integer

Dim cnt As Integer, st As Integer, ed As Integer

s=Text1.Text Call makedata(s)      ‘调用过程

For i=1 To n-1     ‘实现降序排序

For j=n To i+1 Step-1

If{#blank#}2{#/blank#}Then

a(j)=a(j)+a(j-1) : a(j-1)=a(j)-a(j-1) :{#blank#}3{#/blank#}

  End If

 Next j

Next i

‘下列程序段实现计算最多可组队伍

cnt=0: st=1: ed=n

Do While st < ed

 If a(st)+a(ecl) <=120 Then

  List1. AddItem Str(a(st))+“和”+Str(a(ed))+“组队”

  cnt=cnt+1

  st=st+1

  {#blank#}4{#/blank#}

 Else

  st=st+1

 End If

Loop

Label2. Caption=“最多可以组”+Str (cnt)+“组队伍”

End Sub

For i=1 To 9

 For j=10 To i+2 Step-1

  If a(j) < a(j-2) Then

   t=a(j): a(j)=a(j-2): a(j-2)=t

  End If

 Next j

Next i

数组元素a(1)到a(10)的值依次为“10,9,8,7,6,5,4,3,2,1”，执行该程序段后,数组元素a(8)中的值为（  ）

按纪念品价值进行分组，每组总价值不超过限定值w且最多包含两件，要求分组数最少。编写VB程序解决该问题，程序运行时，在文本框Text1中依次输入每件纪念品的价格(不超过w)，以逗号分隔，在文本框Text2中输入限定值w，单击“分组”按钮，在标签Label2上输出最少的分组数。程序运行界面如图所示。

Dim a(1 To 100) As Integer, n As Integer

Function moving( start As Integer, finish As Integer, st As Integer)

'将元素 a(finish)插入到元素 a(start)和元素 a(start+st)之间

Dim i As Integer, k As Integer k = a(finish)

For i = finish - st To start Step -st a(i + st) = a(i)

Next i a(start) = k

End Function

Private Sub Command1_Click()

Dim head As Integer, end1 As Integer, i As Integer, ans As String

' 将待排序的数存储在数组 a 的 a(1)至 a(n)中，并输入元素个数 n，代码略

head = 1: end1 = n + 1

Do While head < end1

If    ①    Then

For i = 1 To head - 1

If a(i) > a(head) Then Exit For

Next i

Call moving(i, head, 1)

head =     ②    

Else

For i = end1 To n

If a(i) < a(head) Then Exit For

Next i

Call moving(    ③    )

End1 = end1 - 1

End If

Loop

For i = 1 To n

ans = ans + Str(a(i))

Next i

Text2.Text = ans End Sub 请回答下列问题：

请回答下列问题：

a = [ 6 , 12 , 9 , 20 , 8 , 11 , 4 ]

for j in range( 1 , len( a ) ) :

    if  a[ j ] < a[ j - 1 ] :

 a[ j ] = a[ j ] + a[ j - 1 ] ;  a[ j - 1 ] = a[ j ] - a[ j - 1 ] ;  a[ j ] = a[ j ] - a[ j - 1 ]

执行该段程序后，列表a的值是（   ）