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浙江省2019-2020学年普通高校招生选考科目信息技术考试试卷(三)

维吉尼亚(Vigenere)密码。如下图所示,分别用行和列表示待加密的字符(明文)和当前字符的密钥,行和列的交叉点的字符即为加密后的结果(密文)。在加密时,密文与明文的字母大小写形式保持一致,如,明文字母为大写,则加密后的密文字母也为大写;当密钥长度不足时重复使用密钥。例如:当明文M=HelloWorld,密钥K=abc时,密文C=HfnlpYosnd。运算过程如下所示:

明文:HelloWorld

密钥:abcabcabca

密文:HfnlpYosnd

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依据上述算法描述设计了如下VB程序。请回答下列问题:

(1)、若明文是Jia,密钥是Pass,则输出的密文是:
(2)、请在横线处填上合适的代码。

Const MIN_ASC = 65       ′字母“A”的ASCII值

Function X2D(x As String) As String     ′字符串小写转成大写

Dim s As String, zf As String, i As Integer

s = “”

For i = 1 To Len(x)

zf = Mid(x, i, 1)

If zf >= “a” And zf <= “z” Then

            s = s +

Else

      s = s + zf
          End If
    Next i
    X2D = s

End Function

Private Sub Command1_Click()

Dim M As String, K As String, C As String, flag As Boolean

Dim i As Integer, t As Integer, ch As Integer, pos As Integer, j As Integer

M = Text1.Text             ′明文

K = Text2.Text              ′密钥

t = Len(K)

K = X2D(K)                   ′将密钥全部转成大写

C = “ ”                      ′加密后的结果

For i = 1 To Len(M)

ch = Asc(Mid(M, i, 1))

flag = False

If ch >= 97 And ch <= 122 Then ch = ch - 32: flag = True

  pos =                ′密钥的字符位置值

If pos = 0 Then pos = t

      j = Asc(Mid(K, pos, 1))               ′密钥字符的ASCII值

     ch = ch - MIN_ASC

     j = j - MIN_ASC

      ch =

      ch = ch + MIN_ASC

  If flag Then ch = ch + 32         ′设置字母的大小写形式

     C = C & Chr(ch)

Next i

Text3.Text = C

End Sub

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