试题 试卷
题型:单选题 题类:常考题 难易度:普通
浙江省绍兴市2019-2020学年高二下学期信息技术期末调测技术试卷
k = 0: s = ""
For i = 1 To n
Next i
Text1.Text = s
方框中的代码由以下四部分组成:
①If a(i) = 0 Then k = k + 1
②If p = k Then s = s + Str(a(i - k))
③a(i - k) = a(i)
④p = k
代码顺序正确的是( )
For i = 1 To 10 If d(i) >= 0 Then t=t+1 List1.AddItem Str(d(i)) Else t=t-1 List2.AddItem Str(d(i))Next则该程序段出错的原因是缺少了( )
n=Len(s) ‘s是待判断的字符串
k=0:j=n
For i=1 To n/ 2
If k=0 Then Labell Caption=“对称”Else Labell.Caption=“不对称”
方框中的代码由以下三部分组成:
①j=j-1 ②If cl <> c2 Then k=k+1 ③cl=Mid(s,i,l):c2=mid(s,j,l)
代码顺序正确的选项是( )
s = "2019Nian12yue3Ri"
For i = Len(s)-1 To 1 step -1
If Mid(s, i, 1) <= "9" And Mid(s, i + 1, 1) >= "A" Then
sum= sum+ Val(Mid(s, i, 1))
End If
运行程序后,变量sum 的值是( )
Dim a(1 To 100) As Integer
Dim b(1 To 100) As Integer
Dim c As Integer
a(1) = 0: a(2) = 2: b(1) = 1: b(2) = 2: c = 0
For i = 2 To 6
a(i + 1) = 2 * a(i) - a(i - 1)
b(i + 1) = b(i) ^ 2 / b(i - 1)
c = c + a(i + 1) + b(i + 1)
Label1.Caption = Str(c)
该程序运行后,Label1中显示的内容是( )
s = input()
k = random.randint(1,len(s)-1) i = 0
while k > 0 and i < len(s)-1:
if s[i] > s[i+1]:
k -= 1
s = s[:i]+s[i+1:]
if i > 0:
i -= 1
else:
i += 1 if k > 0:
s = s[:len(s)-k]
若输入的s值为“8561324”,则执行该程序,输出s的值不可能为 ( )
a=int(input("输入第一个数:"))
b=int(input("输入第二个数:"))
fh=input("输入运算符:")
if {#blank#}1{#/blank#}:
c=a+b
else:
c={#blank#}2{#/blank#}
print("结果是:", {#blank#}3{#/blank#})
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