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题型:综合题 题类:常考题 难易度:困难

浙江省绍兴市诸暨中学2017-2018学年高二下学期信息技术期中考试试卷

【加试题】维吉尼亚密码。如下图所示,分别用行和列表示待加密的字符(明文)和当前字符的密钥,行和列的交叉点的字符即为加密后的结果(密文)。在加密时,密文与明文的字母大小写形式保持一致,如:明文字母为大写,则加密后的密文字母也为大写;当密钥长度不足时重复使用密钥。

例如:当明文M=HelloWorld,密钥K=abc时,密文C=HfnlpYosnd。运算过程如下所示:

明文:HelloWorld

密钥:abcabcabca

密文:HfnlpYosnd

依据上述算法描述设计了如下VB程序。请回答下列问题:

(1)、若明文是Jia,密钥是Pass,则输出的密文是:
(2)、请在划线处填上合适的代码

Const MIN_ASC = 65

Function X2D(x As String) As String

  Dim s As String, zf As String, i As Integer

  s = ""

  For i = 1 To Len(x)

    zf = Mid(x, i, 1)

    If zf >= "a" And zf <= "z" Then

      s=s+

    Else

      s = s + zf

    End If

 Next i

 X2D = s

End Function

Private Sub Command1_Click()

Dim M As String, K As String, C As String, flag As Boolean

Dim i As Integer, t As Integer, ch As Integer, pos As Integer, j As Integer

M = Text1.Text       '明文

K = Text2.Text       '密钥

t = Len(K)

K = X2D(K)

C = ""

For i = 1 To Len(M)

  ch = Asc(Mid(M, i, 1))

  flag = False

  If ch >= 97 And ch <= 122 Then ch = ch - 32: flag = True

  pos=                  '密钥的字符位置值

  If pos = 0 Then pos = t

  j = Asc(Mid(K, pos, 1))      '密钥字符的ASCII值

  ch = ch - MIN_ASC

  j = j - MIN_ASC

  ch=

  ch = ch + MIN_ASC

  If flag Then ch = ch + 32     '设置字母的大小写形式

  C = C & Chr(ch)

Next i

Text3.Text = C

End Sub

举一反三
维吉尼亚(Vigenere)密码。如下图所示,分别用行和列表示待加密的字符(明文)和当前字符的密钥,行和列的交叉点的字符即为加密后的结果(密文)。在加密时,密文与明文的字母大小写形式保持一致,如,明文字母为大写,则加密后的密文字母也为大写;当密钥长度不足时重复使用密钥。例如:当明文M=HelloWorld,密钥K=abc时,密文C=HfnlpYosnd。运算过程如下所示:

明文:HelloWorld

密钥:abcabcabca

密文:HfnlpYosnd

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依据上述算法描述设计了如下VB程序。请回答下列问题:

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