①将该字符的ASCII码值转化为8位二进制数；

  ②将后4位二进制数进行按位取反(1变0，0变1)；

  ③将操作②生成的4位二进制数均左移1位(原第1位变为新的第4位)；

  ④原高4位二进制数连接到新的后4位二进制数成为最终加密后字符的内码。

  例如：字符“a”经过上述加密运算，可得到字符“m”。

程序运行界面如图所示，请改正加框处有误的代码：

Private Sub Command1_Click()

    Dim s As String：Dim sl As String：Dim jg As String

    Dim n As Integer：Dim x As Integer：Dim i As Integer：Dim j As Integer

    Dim a(15)As String

    a(0)=“0000”：a(1)=“0001”：a(2)=“0010”：a(3)=“0011”

    a(4)=“0100”：a(5)=“0101”：a(6)=“0110”：a(7)=“0111¨

    a(8)=“1000”：a(9)=“1001”：a(10)=“1010”：a(11)=“1011¨

    a(12)=“1100”：a(13)=“1101”：a(14)“1110”：a(15)=“1111”

    jg=“ ”

    s=Text1．Text

    For i=1 To Len(s)

        n=Asc(Mid(s，i，1))

        low=n Mod 16

        low=15-low          ‘执行步骤②

        s1=Mid(a(low)，2，3)&Mid(a(low)，1，1)  ‘执行步骤③

        For i=l To 4

            x=x+Val(Mid(s1，j，1))*         ‘⑴{#blank#}1{#/blank#}

        Next j

        x= *16+x                        ‘⑵{#blank#}2{#/blank#}

jg=jg&Chr(x)

    Next i

    Text2．Text=jg

End Sub

For i=1 To 3

k=“”

Fori-1 To 2*i-1

k=k+“*”

Next j

List1.AddItem k

Next i

该程序运行后，在列表框List1中显示的是（  ）

图a

图b

Dim a(1 To 15) As Integer

Private Sub Form_Load()

  Dim i As Integer, t As Integer

  Dim s1 As String, s2 As String

  Randomize

  s1 = ""

  For i = 1 To 15

    a(i) =  ①    

    s1 = s1 + Str(a(i))

  Next i

  Text1.Text = s1

End Sub

Private Sub Com1_Click()

  s2 = ""

  For i = 1 To 15

    s2 =  ②    

  Next i

  Text2.Text = s2

End Sub

Dim a(1 To 5) As Integer

t=0

For i = 1 To 5

  a(i) = Int(Rnd * 30 + 10)

  t = t + a(i) \ 10

Next i

For j = 1 To t \ 3

  If j Mod 2 = 1 Then a(j) = a(j) + 1 Else a(j) = a(j) - 1

Next j

运行程序后，数组a各个元素的值，不可能的是（  ）